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SAY TAHT TO MY FAC NOT ON THE INTRNET AND SEE WHAT HAPPNZYou guys are retards.
You guys are retards.
Doing this now, because I actually know what you want. Will edit shortly.
1. I googled "centroid" because I don't remember which lines that wants. Apparently it wants the "midpoint to opposite vertex" lines. So, let's find the equations of two of these lines.
1a. First we need a midpoint. ((x1+x2/2) , (y1+y2/2)) = ((-3+1)/2 , (15+5)/2) = (-1,10)
1b. Find the line including this sparkly new midpoint, and the unused vertex. This will be one of our centroid lines.
-1,10 5,10
y=mx+b
m= ... 0. That was anticlimatic.
Great, the line is x=10. Let's find another line.
How about 1,5 and 5,10. Midpoint time.
1a. (3,15/2)
1b.
Why am I doing your homework for you? Here is how you do it. (I think. It has been a while since geometry)
Find midpoint of a line.
Use that midpoint and the remaining vertex to find the equation of a new line. This line will pass through the centroid.
Repeat the last two steps, using either of the two remaining triangle lines (not your new one).
Now you have two new line equations, both of which pass through the centroid. Find where they are equal.
(Solve for a variable, substitute, solve for remaining variable, plug that back into original, you know the drill.)
You now have the cords for the centroid. Congrats.
Second problem in progress...
Oh boy, this looks fun. Maybe a bit easier, though.
Find the slope of a triangle line.
Invert said slope. (m= 2 becomes m= -1/2. Not sure if 'invert' is the correct word. Find the perpendicular slope.)
Find the equation of a line with that slope, containing the third as-of-yet-unused-vertex.
Repeat above steps.
You now have two new lines. They are perpendicular to a triangle line and pass through its opposite vertex.
Find where lines are equal. Same as the last problem.
Lines AB and DC look pretty parallel to me......sometimes you just have to assume they are parallel even if they are not marked as parallel.
That's what I thought. Which means a= 145°-b and b=145°-a and c=35°.In this case there is no solution definite solution for angles a and b if you do not presume that lines AB and DC are parallel. So it's safe to assume thus.
damn haven't done any geometry in forever, did you ever get the answer?
I don't even think there is an answer if they aren't parallel.damn haven't done any geometry in forever, did you ever get the answer?
Yup, they were supposed to be parallel lines. But she took my answer anyway.damn haven't done any geometry in forever, did you ever get the answer?
idk but Newton's 3 laws are:Yup, they were supposed to be parallel lines. But she took my answer anyway.
also
View attachment 138694
5-25/4
=-5
acceleration = -5m/s
is this right?
In I, Robot, the robot could choose whether he defended penises or not, meaning he could break Newton's Third Law and smack niqqas in the phallusparts for big laughs.idk but Newton's 3 laws are:
1) A robot must never harm a human being
2) A robot must not let a human being come to harm through inaction, unless doing so conflicts with the first law
3) A robot must defend penises
It's seconds squared, not just seconds (since it's acceleration). Yes it seems about right.Yup, they were supposed to be parallel lines. But she took my answer anyway.
also
View attachment 138694
5-25/4
=-5
acceleration = -5m/s
is this right?
That's Isaac Asimov's 3 laws of robotics..idk but Newton's 3 laws are:
1) A robot must never harm a human being
2) A robot must not let a human being come to harm through inaction, unless doing so conflicts with the first law
3) A robot must defend penises
I don't think Asimov ever mentioned penises.....That's Isaac Asimov's 3 laws of robotics..
I know.I don't think Asimov ever mentioned penises.....
wtf are you on about?Isaac Asimov was the guy who discovered gravity when he dropped an apple on his penis.
He went all "Ow, dat thing darn hit ma penis! It must a' be grav-tee!"
Also while we're on it, Charlie Chaplin's theory of relativity, were peanuts really the cause of Chernobyl's nuclear reactor failing in the 15th century?